2[z-(6z+47)+2]=3(z+9)

Solution for 2[z-(6z+47)+2]=3(z+9) equation:

Simplifying
2[z + -1(6z + 47) + 2] = 3(z + 9)

Reorder the terms:
2[z + -1(47 + 6z) + 2] = 3(z + 9)
2[z + (47 * -1 + 6z * -1) + 2] = 3(z + 9)
2[z + (-47 + -6z) + 2] = 3(z + 9)

Reorder the terms:
2[-47 + 2 + z + -6z] = 3(z + 9)

Combine like terms: -47 + 2 = -45
2[-45 + z + -6z] = 3(z + 9)

Combine like terms: z + -6z = -5z
2[-45 + -5z] = 3(z + 9)
[-45 * 2 + -5z * 2] = 3(z + 9)
[-90 + -10z] = 3(z + 9)

Reorder the terms:
-90 + -10z = 3(9 + z)
-90 + -10z = (9 * 3 + z * 3)
-90 + -10z = (27 + 3z)

Solving
-90 + -10z = 27 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-90 + -10z + -3z = 27 + 3z + -3z

Combine like terms: -10z + -3z = -13z
-90 + -13z = 27 + 3z + -3z

Combine like terms: 3z + -3z = 0
-90 + -13z = 27 + 0
-90 + -13z = 27

Add '90' to each side of the equation.
-90 + 90 + -13z = 27 + 90

Combine like terms: -90 + 90 = 0
0 + -13z = 27 + 90
-13z = 27 + 90

Combine like terms: 27 + 90 = 117
-13z = 117

Divide each side by '-13'.
z = -9

Simplifying
z = -9